TS EAMCET · Maths · Pair of Lines
The equation of the pair of straight lines passing through the point \((2,3)\) and perpendicular to the pair of lines \(3 x^2-4 x y+5 y^2=0\) is \(a x^2+2 h x y+b y^2+2 g x+2 f y+c\) \(=0\) then \(a+b+c+f+g+h=\)
- A 0
- B 52
- C 25
- D -54
Answer & Solution
Correct Answer
(B) 52
Step-by-step Solution
Detailed explanation
A pair of lines perpendicular to \(3 x^2-4 x y+5 y^2=0\) can be given as \(5 x^2+4 x y+3 y^2=0\) is passing through \((2,3)\) Hence,…
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