TS EAMCET · Maths · Circle
A circle \(S \equiv x^2+y^2+2 g x+2 f y+6=0\) cuts another circle \(x^2+y^2-6 x-6 y-6=0\).orthogonally. If the angle between the circles \(S=0\) and \(x^2+y^2+6 x+6 y+2=0\) is \(60^{\circ}\), then the radius of the circle \(S=0\) is
- A 2
- B 1
- C 4
- D 5
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
We know that two circles intersect orthogonally if \(2\left(g g^{\prime}+f f\right)=c+c^{\prime}\) \(\Rightarrow 2(-3 g-3)=6-6 \Rightarrow g=-f\) ....(i) Centre and radius of circle is…
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