TS EAMCET · Maths · Sequences and Series
If \(|a| < 1, b=\sum_{k=1}^{\infty} \frac{a^k}{k}\), then \(a\) is equal to
- A \(\sum_{k=1}^{\infty} \frac{(-1)^k b^k}{k}\)
- B \(\sum_{k=1}^{\infty} \frac{(-1)^{k-1} b^k}{k !}\)
- C \(\sum_{k=1}^{\infty} \frac{(-1)^k b^k}{(k-1) !}\)
- D \(\sum_{k=1}^{\infty} \frac{(-1)^{k-1} b^k}{(k+1) !}\)
Answer & Solution
Correct Answer
(B) \(\sum_{k=1}^{\infty} \frac{(-1)^{k-1} b^k}{k !}\)
Step-by-step Solution
Detailed explanation
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