TS EAMCET · Maths · Limits
If \(f(x)=\left\{\begin{array}{cc}\frac{a \sin x-b x+c x^2+x^3}{2 \log (1+x)-2 x^3+x^4} &, x \neq 0 \\ 0 &, x=0\end{array}\right.\) is continuous at \(x=0\), then
- A \(a=2 b\)
- B \(a=b\)
- C \(a=b=c\)
- D \(b=c\)
Answer & Solution
Correct Answer
(B) \(a=b\)
Step-by-step Solution
Detailed explanation
Given that \(f(x)\) is continuous at \(x=0\), we must have \( \lim_{x \to 0} f(x) = f(0) \). Since \(f(0) = 0\), we need \( \lim_{x \to 0} \frac{a \sin x-b x+c x^2+x^3}{2 \log (1+x)-2 x^3+x^4} = 0 \). Applying L'Hopital's rule (since it is a \(\frac{0}{0}\) form):…
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