TS EAMCET · Maths · Trigonometric Ratios & Identities
\(\cos \left[\cos ^{-1}\left(-\frac{1}{7}\right)+\sin ^{-1}\left(-\frac{1}{7}\right)\right]\) is equal to
- A \(-\frac{1}{3}\)
- B 0
- C \(\frac{1}{3}\)
- D \(\frac{4}{9}\)
Answer & Solution
Correct Answer
(B) 0
Step-by-step Solution
Detailed explanation
\(\cos \left[\cos ^{-1}\left(-\frac{1}{7}\right)+\sin ^{-1}\left(-\frac{1}{7}\right)\right]=\cos \frac{\pi}{2}\) \(\left\lfloor\because \cos ^{-1} x+\sin ^{-1} x=\frac{\pi}{2}\right\rfloor\) \(=0\)
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