TS EAMCET · Chemistry · s Block Elements
What is the correct stability order of \(\mathrm{KO}_2, \mathrm{RbO}_2, \mathrm{CsO}_2\) ?
- A \(\mathrm{KO}_2 \lt \mathrm{CsO}_2 \lt \mathrm{RbO}_2\)
- B \(\mathrm{CsO}_2 \lt \mathrm{KO}_2 \lt \mathrm{RbO}_2\)
- C \(\mathrm{CsO}_2 \lt \mathrm{RbO}_2 \lt \mathrm{KO}_2\)
- D \(\mathrm{KO}_2 \lt \mathrm{RbO}_2 \lt \mathrm{CsO}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{KO}_2 \lt \mathrm{RbO}_2 \lt \mathrm{CsO}_2\)
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Detailed explanation
What is the correct stability order of \(\mathrm{KO}_2, \mathrm{RbO}_2, \mathrm{CsO}_2\) ?
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