TS EAMCET · Maths · Probability
The mean and variance of a binomial variate \(X\) are \(\frac{16}{5}\) and \(\frac{48}{25}\) respectively. If \(P(X\gt1)=1-K\left(\frac{3}{5}\right)^7\), then \(5 K=\)
- A \(19\)
- B \(3\)
- C \(2\)
- D \(11\)
Answer & Solution
Correct Answer
(A) \(19\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & n p=\frac{16}{5} ; n p q=\frac{48}{25} \Rightarrow \frac{16}{5} \times q=\frac{48}{25} \Rightarrow q=\frac{3}{5} \\ p= & \frac{2}{5} \Rightarrow n=8 \Rightarrow P(X\gt1)=1-P(X=0)-P(X=1) \\ = & 1-{ }^8 C_0\left(\frac{3}{5}\right)^8-{ }^8…
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