TS EAMCET · Chemistry · Solid State
The number of unit cells present in \(39 \mathrm{~g}\) of potassium if it crystallizes as body centred cube is ( \(N=\) Avogadro number, At. wt. of potassium \(=39\) )
- A \(\frac{N}{4}\)
- B \(\frac{N}{2}\)
- C \(\frac{N}{3}\)
- D \(N\)
Answer & Solution
Correct Answer
(B) \(\frac{N}{2}\)
Step-by-step Solution
Detailed explanation
Potassium has bcc system Number of mole \(=39 / 39=1\) mole 1 mole of atoms \(=6.022 \times 10^{23}\) atoms \(=N\) \(\because\) In bcc system 2 atoms are present in 1 unit cell. \(\therefore N\) number of atoms are present in \(\frac{N}{2}\) unit cells.
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