TS EAMCET · Chemistry · Hydrogen
The natural relative abundance of isotopes of hydrogen is
- A \({ }_1^1 \mathrm{H}=99.985 \% ;{ }_1^2 \mathrm{D}=0.015 \%\)
- B \({ }_1^1 \mathrm{H}=99.985 \% ;{ }_1^2 \mathrm{D}=0.015 \% ;{ }_1^3 \mathrm{~T}=10^{-16} \%\)
- C \({ }_1^1 \mathrm{H}=99.100 \% ;{ }_1^2 \mathrm{D}=0.900 \%\)
- D \({ }_1^1 \mathrm{H}=99.900 \% ;{ }_1^2 \mathrm{D}=0.10 \% ;{ }_1^3 \mathrm{~T}=10^{-15} \%\)
Answer & Solution
Correct Answer
(B) \({ }_1^1 \mathrm{H}=99.985 \% ;{ }_1^2 \mathrm{D}=0.015 \% ;{ }_1^3 \mathrm{~T}=10^{-16} \%\)
Step-by-step Solution
Detailed explanation
Isotope of hydrogen is hydrogen -2 (also called) deuterium abbreviated as D. Which contains one proton and one neutron and has a natural abundance of only \(0.015 \%\). \[ { }_1^1 \mathrm{H}=99.985 \% ;{ }_1^2 \mathrm{D}=0.015 \% ;{ }_1^3 \mathrm{~T}=10^{-16} \% \]
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