TS EAMCET · Chemistry · States of Matter
The most probable speed of \(\mathrm{O}_2\) molecules at \(T(\mathrm{~K})\) is
- A \(\sqrt{\frac{R T}{4 \pi}}\)
- B \(\sqrt{\frac{R T}{16 \pi}}\)
- C \(\sqrt{\frac{R T}{16}}\)
- D \(\sqrt{\frac{3 R T}{32}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{R T}{16}}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Most probable speed, } v_{\mathrm{mp}}=\sqrt{\frac{2 R T}{M}} \\ & =\sqrt{\frac{2 R T}{32}} \quad \text { (for oxygen, } M=32 \text { ) } \\ & =\sqrt{\frac{R T}{16}} \\ & \end{aligned} \]
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