TS EAMCET · Chemistry · Solutions
The vapour pressure in \(\mathrm{mm}\) of \(\mathrm{Hg}\), of an aqueous solution obtained by adding \(18 \mathrm{~g}\) of glucose \(\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)\) to \(180 \mathrm{~g}\) of water at \(100^{\circ} \mathrm{C}\) is
- A \(7.60\)
- B \(76.0\)
- C \(759\)
- D \(752.4\)
Answer & Solution
Correct Answer
(D) \(752.4\)
Step-by-step Solution
Detailed explanation
According to Raoult's law \[ \frac{p^{\circ}-p_s}{p^{\circ}}=\frac{n_2}{n_1+n_2} \] where, \(p^{\circ}=\) vapour pressure of pure water at \(100^{\circ} \mathrm{C}\) \(=760 \mathrm{mmHg}\). \(p_s=\) vapour pressure of solution at \(100^{\circ} \mathrm{C}\)…
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