TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The increasing order of the atomic radius of \(\mathrm{Si}, \mathrm{S}, \mathrm{Na}, \mathrm{Mg}, \mathrm{Al}\) is
- A \(\mathrm{S} < \mathrm{Si} < \mathrm{Al} < \mathrm{Mg} < \mathrm{Na}\)
- B \(\mathrm{Na} < \mathrm{Al} < \mathrm{Mg} < \mathrm{S} < \mathrm{Si}\)
- C \(\mathrm{Na} < \mathrm{Mg} < \mathrm{Si} < \mathrm{Al} < \mathrm{S}\)
- D \(\mathrm{Na} < \mathrm{Mg} < \mathrm{Al} < \mathrm{Si} < \mathrm{S}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{S} < \mathrm{Si} < \mathrm{Al} < \mathrm{Mg} < \mathrm{Na}\)
Step-by-step Solution
Detailed explanation
As we move from left to right in a period, effective nuclear charge increases. Due to this atomic radius decreases. Thus, correct order of atomic radii of \(3^{\text {rd }}\) period elements is \(\mathrm{Na}>\mathrm{Mg}>\mathrm{Al}>\mathrm{Si}>\mathrm{S}\)
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