TS EAMCET · Maths · Application of Derivatives
The radius of a circular plate is increasing at the rate of \(0.01 \mathrm{~cm} / \mathrm{sec}\). When the radius is \(12 \mathrm{~cm}\), the rate at which the area increases is (in square \(\mathrm{cm} / \mathrm{sec}\) )
- A \(60 \pi\)
- B \(24 \pi\)
- C \(1.2 \pi\)
- D \(0.24 \pi\)
Answer & Solution
Correct Answer
(D) \(0.24 \pi\)
Step-by-step Solution
Detailed explanation
\(\frac{d r}{d t}=0.01 \mathrm{~cm} / \mathrm{s}\), when \(r=12 \mathrm{~cm}\), then \(\frac{d A}{d t}=\) ?…
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