TS EAMCET · Chemistry · Electrochemistry
The \(E^{\circ}\) of \(\begin{aligned}\mathrm{Ce}^{4+} / \mathrm{Ce}^{3+}=1.6 \mathrm{~V} \ \mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}=0.76 \mathrm{~V}\end{aligned}\)
the \(\mathrm{E}^{\circ}\) of \(\mathrm{Fe}^{3+}\) oxidising \(\mathrm{Ce}^{3+}\) is
- A +0.84 V
- B –0.84 V
- C –2.32 V
- D +1.5 V
Answer & Solution
Correct Answer
(B) –0.84 V
Step-by-step Solution
Detailed explanation
\(\mathrm{E}_{\text {cell }}^{\circ}=\mathrm{E}_{o x}^{\circ}+\mathrm{E}_{\text {red }}^{\circ}=(-1.6+0.76)=-0.84 \mathrm{Vd}\)
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