TS EAMCET · Chemistry · Hydrocarbons
Toluene on reaction with reagent A gives X. This \((\mathrm{X})\) forms 2,4-dinitrophenylhydrazone and reduces ammonical silver nitrate solution. Reaction of toluene with another reagent B forms Y, which dissolves in \(\mathrm{NaHCO}_3\) with evolution of \(\mathrm{CO}_2\). What are A and B respectively?
- A \(\mathrm{KMnO}_4\left|\mathrm{OH}^{-}, \Delta \quad ; \mathrm{CrO}_2 \mathrm{Cl}_2\right| \mathrm{CS}_2, \mathrm{H}_3 \mathrm{O}^{+}\)
- B \(\mathrm{CrO}_3+\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}, \mathrm{H}_3 \mathrm{O}^{+} ; \mathrm{CrO}_2 \mathrm{Cl}_2 \mid \mathrm{CS}_2, \mathrm{H}_3 \mathrm{O}^{+}\)
- C \(\mathrm{KMnO}_4 \mid \mathrm{OH}^{-}, \Delta \quad ; \mathrm{CrO}_3-\mathrm{H}_2 \mathrm{SO}_4\)
- D \(\mathrm{CrO}_3+\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}, \mathrm{H}_3 \mathrm{O}^{+} ; \mathrm{KMnO}_4-\mathrm{KOH} / \Delta, \mathrm{H}_3 \mathrm{O}^{+}\)
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(D) \(\mathrm{CrO}_3+\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}, \mathrm{H}_3 \mathrm{O}^{+} ; \mathrm{KMnO}_4-\mathrm{KOH} / \Delta, \mathrm{H}_3 \mathrm{O}^{+}\)
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