TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The electronegativity order of the following elements is
- A \(\mathrm{N}>\mathrm{S}>\mathrm{Te}>1\)
- B \(\mathrm{I}>\mathrm{N}>\mathrm{S}>\mathrm{Te}\)
- C \(\mathrm{N}>\mathrm{I}>\mathrm{S}>\mathrm{Te}\)
- D \(\mathrm{N}>\mathrm{S}>\mathrm{I}>\mathrm{Te}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{N}>\mathrm{I}>\mathrm{S}>\mathrm{Te}\)
Step-by-step Solution
Detailed explanation
Electronegativity is inversely proportional to the atomic size. Smaller the size, greater is the electronegativity. Nitrogen is placed in second period, so it has smallest size and highest electronegativity. Then, iodine belongs to halogen family which are electronegative…
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