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TS EAMCET · Chemistry · Ionic Equilibrium

The degree of dissociation of 0.1 N CH3COOH is (given Ka=1×10-5) approximately _________

  1. A 1×10-6
  2. B 1×10-7
  3. C 1×10-3
  4. D 1×10-2
Verified Solution

Answer & Solution

Correct Answer

(D) 1×10-2

Step-by-step Solution

Detailed explanation

Concentration of solution, C=0.1 N Dissociation constant, Kα=1×10-5 We have to find out degree of dissociation, i.e, α Kα=Cα2 ⇒α=KαC ⇒α=1×10-50.1=1×10-2