TS EAMCET · Physics · Ray Optics
The focal length of biconvex lens made of glass, of equal radii is \(f\). If the lens is dipped in the water, then the focal length becomes (Take, refractive index of glass and water as \(\frac{3}{2}\) and \(\frac{4}{3}\), respectively)
- A 2f
- B 4f
- C \((5 / 3) f\)
- D \((7 / 4) f\)
Answer & Solution
Correct Answer
(B) 4f
Step-by-step Solution
Detailed explanation
Focal length of the biconvex lens is \(f\). Radii are equal, i.e. \(R_1=R_2=R\). \[ { }_a \mu_g=\frac{3}{2} \] \[ { }_a \mu_w=\frac{4}{3} \] According to lens Maker's formula, \[ \therefore \quad \frac{1}{f}=(\mu-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right) \] Here, \(R_1=R\) and…
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