TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Match the following: 
The correct answer is \(\begin{array}{llllllll}A & B & C & D & A & B & C & D\end{array}\)
- A \(\begin{array}{llll}V & \text { I } & \text { III } & \text { II }\end{array}\)
- B \(\begin{array}{llll}V & \text { II } & \text { I } & \text { IV }\end{array}\)
- C \(\begin{array}{llll}\text { III } & V & \text { I } & \text { IV }\end{array}\)
- D \(\begin{array}{llll}\text { III } &IV & \text { I } & \text { II }\end{array}\)
Answer & Solution
Correct Answer
(D) \(\begin{array}{llll}\text { III } &IV & \text { I } & \text { II }\end{array}\)
Step-by-step Solution
Detailed explanation
(A) Trigonal planar \(\rightarrow\) (III) \(\mathrm{BF}_3\), because boron has three (3) valence electrons which are involved in formation of three sigma \((\sigma)\) bonds with \(3 \mathrm{~F}\)-atoms and has no lone pair \((l p)\) of electrons. (B) Tetrahedral \(\rightarrow\)…
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