TS EAMCET · Chemistry · Solutions
\(2.0 \mathrm{~g}\) of a non-electrolyte dissolved in \(100 \mathrm{~g}\) of benzene lowers the freezing point of benzene by \(1.2 \mathrm{~K}\). The freezing point depression constant of benzene is \(5.12 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\). The molar mass of the solute is
- A \(55 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(85 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(155 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(85 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} \Delta T_f & =K_f m=K_f \times \frac{W_2}{M_2} \times \frac{1000}{w_1} \\ 1 \cdot 2 & =\frac{5 \cdot 12 \times 2 \times 1000}{M_2 \times 100} \\ M_2 & =85 \mathrm{~g} \mathrm{~mol}^{-1} \end{aligned} \]
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