TS EAMCET · Chemistry · Electrochemistry
In two separate experiments, the same quantity of electricity was passed through silver and gold solutions [Assume ' \(t\) ' constant] The amounts of Ag and Au deposited are 2.15 and \(1.31 \mathrm{~g}\), respectively. The valency of gold is \([\) Atomic mass of \(\mathrm{Ag}=107.9 ; \mathrm{Au}=197]\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\frac{\mathrm{E}_1}{\mathrm{E}_2} \Rightarrow \frac{2.15}{1.31}=\frac{107.9}{\mathrm{E}_2} \\ & \mathrm{E}_2=65.7\end{aligned}\) Equivalent weight \(=\frac{\text { Atomic mass }}{\text { Valency }}\) Valency of gold…
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