TS EAMCET · Maths · Circle
If \(P\left(\frac{\pi}{4}\right), Q\left(\frac{\pi}{3}\right)\) are two points on the circle \(x^2+y^2-2 x-2 y-1=0\), then the slope of the tangent to this circle which is parallel to the chord \(P Q\) is
- A \(2+\sqrt{2}-\sqrt{3}-\sqrt{6}\)
- B \(\sqrt{2}+\sqrt{3}\)
- C \(2+\sqrt{2}+\sqrt{3}+\sqrt{6}\)
- D \(2+\sqrt{2}\)
Answer & Solution
Correct Answer
(A) \(2+\sqrt{2}-\sqrt{3}-\sqrt{6}\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \(x^2+y^2-2 x-2 y-1=0\) Centre \(=(1,1)\), radius \((r)=\sqrt{1+1+1}=\sqrt{3}\) \(\therefore\) Parametric equation of circle is…
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