TS EAMCET · Chemistry · Ionic Equilibrium
If the solubility of \(\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2\) in water is \(x\) mol L \(\mathrm{L}^{-1}\), its solubility product in \(\operatorname{mol}^5 \mathrm{~L}^{-5}\) is
- A \(6 x^5\)
- B \(36 x^5\)
- C \(64 x^5\)
- D \(108 x^5\)
Answer & Solution
Correct Answer
(D) \(108 x^5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2 \rightleftharpoons 3 \mathrm{Ca}^{2+}+2 \mathrm{PO}_4^{3-}\)…
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