TS EAMCET · Chemistry · States of Matter
If the kinetic energy in \(\mathrm{J}\), of \(\mathrm{CH}_4\) (molar mass \(=16 \mathrm{~g} \mathrm{~mol}^{-1}\) ) at \(T(\mathrm{~K})\) is \(X\), the kinetic energy in \(\mathrm{J}\), of \(\mathrm{O}_2\) (molar mass \(=32 \mathrm{~g} \mathrm{~mol}^{-1}\) ) at the same temperature is
- A \(x\)
- B \(2 X\)
- C \(X^2\)
- D \(\frac{X}{2}\)
Answer & Solution
Correct Answer
(A) \(x\)
Step-by-step Solution
Detailed explanation
At same temperature, kinetic energy of both the gases will be same. In short \[ \begin{array}{lc} \because & \mathrm{KE} \propto \sqrt{T} \\ \therefore & \mathrm{KE}_{\left(\mathrm{CH}_4\right)}=\mathrm{KE}_{\left(\mathrm{O}_2\right)}=X \end{array} \] (for all gases)
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