TS EAMCET · Chemistry · Thermodynamics (C)
\(\Delta H_f^{\circ}\) values (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) for graphite, diamond and \(C_{60}\) are respectively
- A \(0 ; 1.9 ; 38.1\)
- B \(1.8 ; 1.9 ; 38.1\)
- C \(0 ; 0 ; 21.4\)
- D \(1.8 ; 1.9 ; 2.0\)
Answer & Solution
Correct Answer
(A) \(0 ; 1.9 ; 38.1\)
Step-by-step Solution
Detailed explanation
\(\because\) Graphite is the most stable state of carbon and its \(\Delta H_f^{\circ}\) is considered as zero ( \(\because\) has more van der Waals' force) also \(\Delta H_f^{\circ}\) for \(\mathrm{C}_{60}>\Delta H_f^{\circ}\) for diamond. \(\Delta H_f{ }^{\circ}\) values of…
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