TS EAMCET · Chemistry · Thermodynamics (C)
Enthalpy of formation of \(\mathrm{CO}(\mathrm{g}), \mathrm{CO}_2(\mathrm{~g})\) are \(-110,-393\) \(\mathrm{kJ} \mathrm{mol}^{-1}\) respectively. The enthalpy of combustion of CO (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) is
- A \(-283.0\)
- B \(-110.5\)
- C \(504\)
- D \(-221.2\)
Answer & Solution
Correct Answer
(A) \(-283.0\)
Step-by-step Solution
Detailed explanation
For the combustion of \(\mathrm{CO}\) :- \[ \mathrm{CO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g}) \] For \(\mathrm{O}_2(\mathrm{~g}), \Delta \mathrm{H}_{\mathrm{f}}^{\circ}=0.0 \mathrm{~kJ} / \mathrm{mol}\).…
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