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TS EAMCET · Maths · Probability

The numbers \(2,3,5,7,11,13\) are written on six distinct paper chits. If 3 of them are chosen at random, then the probability that the sum of the numbers on the obtained chits is divisible by 3 , is

  1. A \(\frac{7}{20}\)
  2. B \(\frac{6}{20}\)
  3. C \(\frac{5}{20}\)
  4. D \(\frac{1}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{7}{20}\)

Step-by-step Solution

Detailed explanation

Given numbers \(2,3,5,7,11,13\) Total no. of ways 3 chits can be choosen \(={ }^6 C_3\) Now, we observe the outcomes for sum divisible by 3 . So, the pairs whose sum divisible by 3 are \((2,3,7)\), \((2,3,13),(2,5,11),(3,5,7),(3,5,13),(3,7,11)\), \((3,11,13)\) Hence, required…