TS EAMCET · Chemistry · Structure of Atom
The wavelength of second line of Balmer series of hydrogen atom is \(\lambda \mathrm{nm}\). What is the wavelength of first line of Lyman series of \(\mathrm{He}^{+}\)ion (in \(\mathrm{nm}\) )?
- A \(\frac{\lambda}{16}\)
- B \(\frac{16}{\lambda}\)
- C \(\frac{16}{3 \lambda}\)
- D \(\frac{3 \lambda}{16}\)
Answer & Solution
Correct Answer
(A) \(\frac{\lambda}{16}\)
Step-by-step Solution
Detailed explanation
\[ \frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{\mathrm{n}_1{ }^2}-\frac{1}{\mathrm{n}_2{ }^2}\right] \] For the second line of Balmer series of \(\mathrm{H}\)-atom:-…
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