TS EAMCET · Chemistry · Electrochemistry
Consider the following electrode processes of a cell, \[ \mathrm{Cl}^{-} \rightarrow \frac{1}{2} \mathrm{Cl}_2+e^{-} \quad\left[\mathrm{MCl}+e^{-} \rightarrow M+\mathrm{Cl}^{-}\right] \] If EMF of this cell is \(-1.140 \mathrm{~V}\) and \(E^{\circ}\) value of the cell is \(-0.55 \mathrm{~V}\) at \(298 \mathrm{~K}\), the value of the equilibrium constant of the sparingly soluble salt \(M \mathrm{Cl}\) is in the order of
- A \(10^{-10}\)
- B \(10^{-8}\)
- C \(10^{-7}\)
- D \(10^{-11}\)
Answer & Solution
Correct Answer
(A) \(10^{-10}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{MCl}+e^{-} \longrightarrow M+\mathrm{Cl}^{-}\)cathode (reduction) \(\mathrm{Cl}^{-} \longrightarrow \frac{1}{2} \mathrm{Cl}_2+e^{-}\)anode (oxidation) \[ \mathrm{MCl} \rightarrow \mathrm{M}+\frac{1}{2} \mathrm{Cl}_2 \] The \(K_C\) of the cell reaction is calculated…
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