TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Identify the option in which the molecules are arranged in the correct order of their dipole moments.
- A \(\mathrm{CO}_2 < \mathrm{H}_2 \mathrm{O} < \mathrm{H}_2 \mathrm{~S}\)
- B \(\mathrm{HF} < \mathrm{HCl} < \mathrm{HBr}\)
- C \(\mathrm{BF}_3 < \mathrm{NF}_3 < \mathrm{NH}_3\)
- D \(\mathrm{CH}_4 < \mathrm{CHCl}_3 < \mathrm{CCl}_4\)
Answer & Solution
Correct Answer
(C) \(\mathrm{BF}_3 < \mathrm{NF}_3 < \mathrm{NH}_3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{BF}_3\) is non-polar due to equivalent bonds arranged in symmetrical trigonal planar geometry. Among \(\mathrm{NF}_3\) and \(\mathrm{NH}_3, \mathrm{NH}_3\) is more polar as the dipole moments of the three \(\mathrm{N}-\mathrm{H}\) bonds get added whereas they cancel…
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