TS EAMCET · Chemistry · Hydrogen

Assertion (A) : \(\mathrm{NaCl}\) is less soluble in heavy water than in ordinary water. Reason (R) : Dielectric constant of ordinary water is more than that of heavy water. The correct answer is

A Both (A) and (R) are true and (R) is the correct explanation of (A)
B Both \((\mathrm{A})\) and \((\mathrm{R})\) are true but \((\mathrm{R})\) is not the correct explanation of (A)
C (A) is true, but (R) is not true
D (A) is not true, but (R) is true

Verified Solution

Answer & Solution

Correct Answer

(A) Both (A) and (R) are true and (R) is the correct explanation of (A)

Step-by-step Solution

Detailed explanation

\(\mathrm{NaCl}\) is less soluble in heavy water than in ordinary water because dielectric constant of ordinary water \((i e, 81)\) is more than that of heavy water (ie, 80).

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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