TS EAMCET · Chemistry · Electrochemistry
A and B are two metals. The standard reduction potential of \(\mathrm{A}^{+}(\mathrm{aq}) / \mathrm{A}(\mathrm{s})\) and \(\mathrm{B}^{+}(\mathrm{aq}) / \mathrm{B}(\mathrm{s})\) are \(-0.5 \mathrm{~V}\) and \(+0.5 \mathrm{~V}\) respectively. What is the \(\log K_C\) value for the following reaction at \(298 \mathrm{~K}\) ? \[ \mathrm{A}(\mathrm{s})+\mathrm{B}^{+}(\mathrm{aq}) \rightleftharpoons \mathrm{A}^{+}(\mathrm{aq})+\mathrm{B}(\mathrm{s}) \] \(\left(\right.\) Given : \(\left.\frac{2.303 R T}{F}=0.06 \mathrm{~V}\right)\)
- A \(\frac{6}{100}\)
- B \(\frac{100}{6}\)
- C \(\frac{}{200}\)
- D \(\frac{200}{6}\)
Answer & Solution
Correct Answer
(B) \(\frac{100}{6}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \Delta \mathrm{G}^{\circ}=\mathrm{nFE}_{\text {cell }}^{\circ} \\ & \Delta \mathrm{G}^{\circ}=-\mathrm{RT} \ln \mathrm{K}_{\mathrm{c}} \\ & \therefore \quad \mathrm{nFE}_{\text {cell }}^{\circ}=-\mathrm{RT} \ln \mathrm{K}_{\mathrm{c}}=\frac{-2.303…
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