TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Identify the correct set of \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\) ion. (hybridisation of \(\mathrm{Co}^{3+}\), type of complex, number of unpaired electrons in the complex ion respectively)
- A \(\mathrm{d}^2 \mathrm{sp}^3\), inner orbital complex, zero
- B \(\mathrm{sp}^3 \mathrm{~d}^2\), outer orbital complex, three
- C \(\mathrm{d}^2 \mathrm{sp}^3\), inner orbital complex, two
- D \(\mathrm{sp}^3 \mathrm{~d}^2\), outer orbital complex, zero
Answer & Solution
Correct Answer
(A) \(\mathrm{d}^2 \mathrm{sp}^3\), inner orbital complex, zero
Step-by-step Solution
Detailed explanation
\(\mathrm{Co}\) in \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\) is in +3 state as \(\mathrm{NH}_3\) is a neutral ligand. Since there are a total of six ligands, the hybridization state will be either \(\mathrm{d}^2 \mathrm{sp}^3\) or…
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