TS EAMCET · Chemistry · Some Basic Concepts of Chemistry
\(19 \mathrm{~g}\) of a mixture containing \(\mathrm{NaHCO}_3\) and \(\mathrm{Na}_2 \mathrm{CO}_3\) on complete heating liberated \(1.12 \mathrm{~L}\) of \(\mathrm{CO}_2\) at STP. The weight of the remaining solid was \(15.9 \mathrm{~g}\). What is the weight (in g) of \(\mathrm{Na}_2 \mathrm{CO}_3\) in the mixture before heating?
- A 8.4
- B 15.9
- C 4
- D 10.6
Answer & Solution
Correct Answer
(D) 10.6
Step-by-step Solution
Detailed explanation
Molecular weight of \(\mathrm{NaHCO}_3=23+1+12+48=84\) Molecular weight of \(\mathrm{Na}_2 \mathrm{CO}_3=46+12+48=106\) Hence, total weight \(=84+106=190\) \(\because\) In \(190 \mathrm{~g}\) of a mixture, weight of \(\mathrm{Na}_2 \mathrm{CO}_3\) is \(=106\) \(\therefore\) In…
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