TS EAMCET · Chemistry · States of Matter

$4.4$ grams of a gas at $0 ° C$ and $0.82 atm$ pressure occupies a volume of $2.73 L$ . The gas can be

A $O_{2}$
B $CO$
C ${NO}_{2}$
D ${CO}_{2}$

Verified Solution

Answer & Solution

Correct Answer

(D) ${CO}_{2}$

Step-by-step Solution

Detailed explanation

Ideal gas equation PV=nRT=wMRT where M =molecular weight w=4.4gm, T=273k , R=0.082, P=0.82atm V=2.73litre ⇒ 0.82×2.73=4.4M×0.082×273⇒ M =4.4×0.082×273.82×2.73= 44 CO2 molecular weight is 44

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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4.4 grams of a gas at 0°C and 0.82 atm pressure occupies a volume of 2.73 L. The gas can be

Step-by-step Solution

$4.4$ grams of a gas at $0 ° C$ and $0.82 atm$ pressure occupies a volume of $2.73 L$ . The gas can be