TS EAMCET · Chemistry · Solid State
An element with molar mass \(2.7 \times 10^{-2} \mathrm{~kg} \mathrm{~mol}^{-1}\) forms a cubic unit cell with edge length of 405 pm . If its density is \(2.7 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}\), the number of atoms present in one unit cell of it is (Given : \(\left.\mathrm{N}_{\mathrm{A}}=6.023 \times 10^{23} \mathrm{~mol}^{-1}\right)\)
- A 2
- B 4
- C 6
- D 12
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
The number of atoms present in one unit of element can be calculated by…
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