MHT CET · Maths · Trigonometric Ratios & Identities
If \(\sin \mathrm{A}+\sin \mathrm{B}=x\) and \(\cos \mathrm{A}+\cos \mathrm{B}=\mathrm{y}\), then \(\sin (\mathrm{A}+\mathrm{B})=\)
- A \(\frac{2 x y}{x^2+y^2}\)
- B \(\frac{x y}{x^2+y^2}\)
- C \(\frac{2 x y}{y^2-x^2}\)
- D \(\frac{x y}{y^2-x^2}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 x y}{x^2+y^2}\)
Step-by-step Solution
Detailed explanation
\(x = 2 \sin\left(\frac{\mathrm{A}+\mathrm{B}}{2}\right) \cos\left(\frac{\mathrm{A}-\mathrm{B}}{2}\right)\) \(y = 2 \cos\left(\frac{\mathrm{A}+\mathrm{B}}{2}\right) \cos\left(\frac{\mathrm{A}-\mathrm{B}}{2}\right)\)
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