MHT CET · Maths · Three Dimensional Geometry
If the plane \(\frac{x}{2}-\frac{y}{3}-\frac{z}{5}=1\) cuts the co-ordinate axes in point \(A, B, C\) respectively, then the area of the triangle \(A B C\) is
- A \(\frac{17}{2}\) sq. units
- B \(\frac{19}{2}\) sq. units
- C \(\frac{11}{2}\) sq. units
- D \(\frac{15}{2}\) sq. units
Answer & Solution
Correct Answer
(B) \(\frac{19}{2}\) sq. units
Step-by-step Solution
Detailed explanation
A \((2,0,0)\), B \((0,-3,0)\), C \((0,0,-5)\) Area \(=\frac{1}{2}\sqrt{(2 \cdot (-3))^2 + ((-3) \cdot (-5))^2 + ((-5) \cdot 2)^2}\)
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