MHT CET · Physics · Thermodynamics
The change in internal energy of the mass of a gas, when the volume changes from ' \(\mathrm{V}\) ' to ' \(2 \mathrm{~V}\) ' at constant pressure ' \(\mathrm{P}\) ' is \(\left(\gamma=\right.\) Ratio of \(\mathrm{C}_{\mathrm{p}}\) to \(\left.\mathrm{C}_{\mathrm{v}}\right)\)
- A \(\frac{\mathrm{PV}}{(\gamma-1)}\)
- B \(\frac{P}{(\gamma-1)}\)
- C PV
- D \(\frac{\gamma \mathrm{PV}}{(\gamma-1)}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{PV}}{(\gamma-1)}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T} \\ & =\mathrm{n} \frac{\mathrm{R}}{\gamma-1} \Delta \mathrm{T} \\ & =\frac{\mathrm{P} \Delta \mathrm{V}}{\gamma-1}=\frac{\mathrm{PV}}{\gamma-1}\end{aligned}\)
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