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MHT CET · Maths · Sequences and Series

For a sequence if \(S_{n}=\frac{5^{n}-2^{n}}{2^{n}}\), then its fourth term is

  1. A \(\frac{375}{16}\)
  2. B \(\frac{375}{8}\)
  3. C \(\frac{251}{8}\)
  4. D \(\frac{251}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{375}{16}\)

Step-by-step Solution

Detailed explanation

\(s_{n}=\frac{5^{n}-2^{n}}{2^{n}} ; s_{n-1}=\frac{5^{n-1}-2^{n-1}}{2^{n-1}}\)
\(\begin{aligned} T_{n} &=s_{n}-s_{n-1} \\ T_{n} &=\frac{5^{n}-2^{n} \cdot 5^{n-1}}{2^{n}} \\ T_{4} &=\frac{5^{4}-2 \cdot 5^{3}}{2^{4}} \\ &=\frac{625-250}{16} \\ &=\frac{375}{16} \end{aligned}\)