KCET · Physics · Nuclear Physics
What is the de Broglie wavelength of the electron accelerated through a potential difference of
\( 100 \) Volt?
- A \( 12.27 Å \)
- B \( 1.227 Å \)
- C \( 0.1227 \mathrm{~A} \)
- D \( 0.001227 \stackrel{0}{A} \)
Answer & Solution
Correct Answer
(B) \( 1.227 Å \)
Step-by-step Solution
Detailed explanation
de Broglie wavelength of electron accelerated through a potential difference of \( V \) volt is given as
\[
\lambda=\frac{12.27}{\sqrt{V}}
\]
Here \( V=100 \) Volt
Therefore, \( \lambda=\frac{12.27}{\sqrt{100}}=\frac{12.27}{10}=1.227 \mathrm{AA} \)
\[
\lambda=\frac{12.27}{\sqrt{V}}
\]
Here \( V=100 \) Volt
Therefore, \( \lambda=\frac{12.27}{\sqrt{100}}=\frac{12.27}{10}=1.227 \mathrm{AA} \)
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