KCET · Physics · Electrostatics
The total electric flux through a closed spherical surface of radius \(r\) enclosing an electric dipole of dipole moment \(2 a q\) is (Give \(\varepsilon_0=\) permittivity of free space)
- A zero
- B \(\frac{q}{\varepsilon_0}\)
- C \(\frac{2 q}{\varepsilon_0}\)
- D \(\frac{8 \pi r^2 q}{\varepsilon_0}\)
Answer & Solution
Correct Answer
(A) zero
Step-by-step Solution
Detailed explanation
Since, net charge on electric dipole is zero.
\(\therefore\) Hence, according to Gauss's law,
Total electric flux, \(\phi=\frac{q_{\mathrm{net}}}{\varepsilon_0}=\frac{0}{\varepsilon_0}=0\)
\(\therefore\) Hence, according to Gauss's law,
Total electric flux, \(\phi=\frac{q_{\mathrm{net}}}{\varepsilon_0}=\frac{0}{\varepsilon_0}=0\)
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