KCET · Chemistry · Surface Chemistry
A colloidal solution is subjected to an electric field than colloidal particles more towards anode. The amount of electrolytes of \(\mathrm{BaCl}_{2}, \mathrm{AlCl}_{3}\) and \(\mathrm{NaCl}\) required to coagulate the given colloid is in the order
- A \(\mathrm{NaCl}>\mathrm{BaCl}_{2}>\mathrm{AlCl}_{3}\)
- B \(\mathrm{BaCl}_{2} < \mathrm{AlCl}_{3}>\mathrm{NaCl}\)
- C \(\mathrm{AlCl}_{3}=\mathrm{NaCl}=\mathrm{BaCl}_{2}\)
- D \(\mathrm{AlCl}_{3}>\mathrm{BaCl}_{2}>\mathrm{NaCl}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{NaCl}>\mathrm{BaCl}_{2}>\mathrm{AlCl}_{3}\)
Step-by-step Solution
Detailed explanation
The amount of electrolyte required to coagulate the given colloid is in order
\(\mathrm{NaCl}>\mathrm{BaCl}_{2} < \mathrm{AlCl}_{3}\)
Because as colloids move towards anode they must be negatively charge.
According to Hardy Schulze rule,
Coagulation value
\(\propto \frac{1}{\text { Coagulating power (Charge an electrolyte) }}\)
The charge on the electrolyte; \(\mathrm{Na}^{+}, \mathrm{Ba}^{2+}\) and \(\mathrm{Al}^{3+}\) are 1,2 and 3 respectively.
\(\mathrm{NaCl}>\mathrm{BaCl}_{2} < \mathrm{AlCl}_{3}\)
Because as colloids move towards anode they must be negatively charge.
According to Hardy Schulze rule,
Coagulation value
\(\propto \frac{1}{\text { Coagulating power (Charge an electrolyte) }}\)
The charge on the electrolyte; \(\mathrm{Na}^{+}, \mathrm{Ba}^{2+}\) and \(\mathrm{Al}^{3+}\) are 1,2 and 3 respectively.
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