KCET · Physics · Current Electricity
The effective resistance between \( \mathrm{P} \) and \( \mathrm{Q} \) for the following network is
- A \( \frac{1}{12} \Omega \)
- B \( 21 \Omega \)
- C \( 12 \Omega \)
- D \( \frac{1}{21} \Omega \)
Answer & Solution
Correct Answer
(C) \( 12 \Omega \)
Step-by-step Solution
Detailed explanation
The two \( 3 \Omega \) resistance are in series, therefore their equivalent resistance \( =6 \Omega \)
Thus, the network reduces to the circuit as follows:
Now, the two \( 6 \Omega \) resistance are in parallel, therefore their equivalent resistance \( =3 \Omega \)
Thus, the network reduces to the circuit as follows:
Now, all the resistance are in series therefore their equivalent resistance \( =12 \Omega \)
Therefore, effective resistance between \( P \) and \( Q \) is \( 12 \Omega \).
Thus, the network reduces to the circuit as follows:
Now, the two \( 6 \Omega \) resistance are in parallel, therefore their equivalent resistance \( =3 \Omega \)
Thus, the network reduces to the circuit as follows:
Now, all the resistance are in series therefore their equivalent resistance \( =12 \Omega \)
Therefore, effective resistance between \( P \) and \( Q \) is \( 12 \Omega \).
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