KCET · Physics · Current Electricity
10 identical cells each potential \(E\) and internal resistance \(r\) are connected in series to form a closed circuit
- A \(3 E\)
- B \(13 E\)
- C \(7 E\)
- D \(10 E\)
Answer & Solution
Correct Answer
(A) \(3 E\)
Step-by-step Solution
Detailed explanation
According to given situation, total voltage of 10 cells \(=10 E\)
Total resistance of 10 cells \(=10 \mathrm{r}\)
\(\therefore\) Current in the circuit, \(I=\frac{10 E}{10 r}=\frac{E}{r}\)
Potential difference across 3 cells,
\(V=I \times(3 r)=\frac{E}{r} \times 3 r=3 E\)
Hence, ideal voltmeter will read \(3 E\).
Total resistance of 10 cells \(=10 \mathrm{r}\)
\(\therefore\) Current in the circuit, \(I=\frac{10 E}{10 r}=\frac{E}{r}\)
Potential difference across 3 cells,
\(V=I \times(3 r)=\frac{E}{r} \times 3 r=3 E\)
Hence, ideal voltmeter will read \(3 E\).
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