KCET · Chemistry · Hydrocarbons
The hydrolysis of optically active \( 2 \)-bromobutane with aqueous \( \mathrm{NaOH} \) result in the formation of
- A \( (+) \) butan-2-ol
- B (-) butan-2-ol
- C ( \( \pm \) ) butan-1-ol
- D ( \( \pm \) ) butan-2-ol
Answer & Solution
Correct Answer
(D) ( \( \pm \) ) butan-2-ol
Step-by-step Solution
Detailed explanation
2-Bromobutane is a secondary alkyl halide, therefore, hydrolysis will proceed through \( S_{N} 1 \) mechanisms, hence, racemic
mixture will be formed, that is, (±) butan-2-ol.


(+) Butan-2-ol
(-) Butan-2-ol
mixture will be formed, that is, (±) butan-2-ol.


(+) Butan-2-ol
(-) Butan-2-ol
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