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KCET · Chemistry · Hydrocarbons

The hydrolysis of optically active \( 2 \)-bromobutane with aqueous \( \mathrm{NaOH} \) result in the formation of

  1. A \( (+) \) butan-2-ol
  2. B (-) butan-2-ol
  3. C ( \( \pm \) ) butan-1-ol
  4. D ( \( \pm \) ) butan-2-ol
Verified Solution

Answer & Solution

Correct Answer

(D) ( \( \pm \) ) butan-2-ol

Step-by-step Solution

Detailed explanation

2-Bromobutane is a secondary alkyl halide, therefore, hydrolysis will proceed through \( S_{N} 1 \) mechanisms, hence, racemic
mixture will be formed, that is, (±) butan-2-ol.


(+) Butan-2-ol
(-) Butan-2-ol