KCET · Physics · Current Electricity
In the circuit shown, the currents \(i_{1}\) and \(i_{2}\) are
- A \(i_{1}=1.5 \mathrm{~A}, i_{2}=0.5 \mathrm{~A}\)
- B \(i_{1}=0.5 \mathrm{~A}, i_{2}=1.5 \mathrm{~A}\)
- C \(i_{1}=1 \mathrm{~A}, i_{2}=3 \mathrm{~A}\)
- D \(i_{1}=3 \mathrm{~A}, i_{2}=1 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(i_{1}=0.5 \mathrm{~A}, i_{2}=1.5 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Resistance \(R=\frac{12 \times 4}{12+4}+2=\frac{48}{16}+2=5 \Omega\) Electric current \(I=\frac{E}{R+r}=\frac{12}{6}=2 \mathrm{~A}\)
\(I_{1}+I_{2}=2 \mathrm{~A} \)
\(I \propto \frac{1}{R} \)
\(\therefore I_{2}=1.5 \mathrm{~A}, I_{1}=0.5 \mathrm{~A}\)
\(I_{1}+I_{2}=2 \mathrm{~A} \)
\(I \propto \frac{1}{R} \)
\(\therefore I_{2}=1.5 \mathrm{~A}, I_{1}=0.5 \mathrm{~A}\)
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