KCET · Physics · Alternating Current
In series \(L C R\) circuit at resonance, the phase difference between voltage and current is
- A Zero
- B \(\pi\)
- C \(\frac{\pi}{4}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(A) Zero
Step-by-step Solution
Detailed explanation
In \(L-C-R\) series resonance circuit,
\(X_L=X_C\)
\(\therefore \tan \phi=\frac{X_L-X_C}{R}=\frac{0}{R}=0\)
\(\Rightarrow \phi=0^{\circ}\)
\(X_L=X_C\)
\(\therefore \tan \phi=\frac{X_L-X_C}{R}=\frac{0}{R}=0\)
\(\Rightarrow \phi=0^{\circ}\)
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