KCET · Physics · Capacitance
If a charge on the body is \( 1 \mathrm{nC} \), then how many electrons are present on the body?
- A \( 1.6 \times 10^{19} \)
- B \( 6.25 \times 10^{9} \)
- C \( 6.25 \times 10^{27} \)
- D \( 6.25 \times 10^{28} \)
Answer & Solution
Correct Answer
(B) \( 6.25 \times 10^{9} \)
Step-by-step Solution
Detailed explanation
We know; \(q=n e \Rightarrow n=\frac{q}{e}\)
where \(\mathrm{q}\) is charge; \(\mathrm{n}\) is number of electrons; e is electronic charge
Given, \(q=1 \mathrm{nC}=1 \times 10^{-9} \mathrm{C}\)
If a charge on body is \(1 \mathrm{nC}\), then \(6.25 \times 10^{9}\)
where \(\mathrm{q}\) is charge; \(\mathrm{n}\) is number of electrons; e is electronic charge
Given, \(q=1 \mathrm{nC}=1 \times 10^{-9} \mathrm{C}\)
If a charge on body is \(1 \mathrm{nC}\), then \(6.25 \times 10^{9}\)
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