KCET · Chemistry · Classification of Elements and Periodicity in Properties
Which of the following is the correct order of radius?
- A \( \mathrm{H}^{-}>\mathrm{H}>\mathrm{H}^{+} \)
- B \( \mathrm{Na}^{+}>\mathrm{F}^{-}>\mathrm{O}^{2-} \)
- C \( \mathrm{F}^{-}>\mathrm{O}^{2-}>\mathrm{Na}^{+} \)
- D \( \mathrm{Al}^{3+}>\mathrm{Mg}^{2+}>\mathrm{N}^{3-} \)
Answer & Solution
Correct Answer
(A) \( \mathrm{H}^{-}>\mathrm{H}>\mathrm{H}^{+} \)
Step-by-step Solution
Detailed explanation
The size of anion is always higher than that of the parentatom due to the decrease in effective nuclear charge on anion
\( \left(Z_{\text {eff }}\right) \) while, the size of cation is always smaller than parent atom due to lesser \( \left(Z_{\text {eff }}\right) \) than parent atom. Hence, the
correct given order is \( H^{-}>H>H^{+} \)
\( \left(Z_{\text {eff }}\right) \) while, the size of cation is always smaller than parent atom due to lesser \( \left(Z_{\text {eff }}\right) \) than parent atom. Hence, the
correct given order is \( H^{-}>H>H^{+} \)
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